Multiplication with 25 and 125 |

Normally candidates have solved multiplications with 25, 125 in a way of a lengthy process in competitive exams. There has a shortcut method done by easy steps. By following the shortcut method, a lengthy process problem will take a less time to complete when compared to the normal method.

## How to solve multiplications with 25, 125 in competitive exams?

In view of the competitive exams, candidates solve a multiplication problem with 25, 125 in a way of writing number side by side. Finally, outcome answer will take 2 to 3 minutes. By following

**, candidates can solve more problems in the given time period. A candidate can solve about 2 to 3 problems in just 3 minutes. A lot of time have been saved. Time saving is a preferable point in the view of the competitive exams***shortcut methods*Don't Use Paper Work

### Shortcut method of multiplications with 25!

Example:

32 x 25 = ?

25 is the 4th part of 100. So we can write 25 as (100/4).

When multiplying with 32 x 25

**We can write**

**32 x 100 / 4**

= 8 x 100

= 800

32 x 25 = 800

Method-II:

We can use another method which is very easy

32 x 25 = ?

32 / 4 = ?

The remainder is zero (0) when this happens we have to put double zeros (00) at the end of the result.

So in this case 800 is the answer

32 x 25 = 800

The following are the numbers have to be put in the result, when the remainder is zero and non-zero

Reminder

0 = 00

1 = 25

2 = 50

3 = 75

Practice problems with 25:

45 x 25 = ?

59 x 25 = ?

84 x 25 = ?

### Shortcut method of Multiplication with 125

Example:

32 x 125 = ?

125 is the 8th part of 1000. So we can write 125 as (1000/8).

When multiplying with 32 x 125

We can write

32x 1000 / 8 =?

32 x 125 = 4000 is the answer

**Method-II:**

We can use another method which is very easy to solve multiplications with 125

**32 x 125 = ?**

**32 / 8 =?**

~~32~~ / ~~8~~ = 4

**In this case, the remainder is zero (0). Candidates have to put three zeros (000) after the answer.**

**32 x 125 = 4000**

The following are the numbers have to be put in the result, when the remainder is zero and non-zero

0 = 000

1 = 125

2 = 250

3 = 375

#### Practice problems with 125:

33 x125 = ?

34 x 125 = ?

35 x 125 = ?

576 x 125 = ?

832x 125 = ?

757 x 125 = ?

561 x 125 = ?

NOTE: You practice like this, you will become topper in competitive exams.

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